In an examination, 9% of the candidates passed and 46 failed. How many candidates appeared?

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Solution

Let the total number of candidates be x.
Number of candidates who failed = 46
Number of candidates who passed = 92% of x
According to the given condition,
92% of x = x - 46
⇒ (92/100) x = x - 46
⇒ 92x = 100x - 4600
⇒ -8x = - 4600
⇒ x = 4600/8 =
Number of candidates who appeared for the examination = 575

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