Question

In an examination in which full marks were 800, A gets 20% more than S, B gets 20% more than C, and C gets 15% less than D. If A got 576, what percentage of full marks did D get (approximately) ?

• A. 45.7%
• B. 58.8%
• C. 51.2%
• D. 61.7%

Answer 1

The correct option is B 58.8%

Let the marks got by D=x
Marks of C=$.85x$
Marks of B=$1.2\times .85\times x$
Marks of A=$1.2\times 1.2\times .85\times x$
Given Marks of A=576
$\therefore 1.2\times 1.2\times .85\times x=576$
$\Rightarrow x=\frac{576}{1.2\times 1.2\times 8.5}$
$\Rightarrow x=\frac{400}{.85}$
$\Rightarrow =\frac{8000}{17}$
Percentage marks =$\frac{8000}{17}\times \frac{1}{800}\times 100=58.82$