In an examination there were $640$ boys and $360$ girls. $60 %$ of the boys and $80 %$ of the girls were successful. The percentage of failures was:

20

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60

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30.5

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32.8

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Solution

The correct option is D $32.8$
Number of failures
$= 40 %$ of $640 + 20 %$ of $360$
$= \frac{40}{100} \times 640 + \frac{20}{100} \times 360 = 256 + 72 = 328$
Total number of students $= 640 + 360 = 1000$
$∴ %$ of failures $= (\begin{matrix} \frac{328}{1000} \times 100 \end{matrix}) % = 32.8 %$ .

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In an examination there were 640 boys and 360 girls. 60% of the boys and 80% of the girls were successful. The percentage of failures was:

The correct option is D 32.8Number of failures=40% of 640+20% of 360=40100×640+20100×360=256+72=328Total number of students =640+360=1000∴% of failures =(3281000×100)%=32.8%.

In an examination there were $640$ boys and $360$ girls. $60 %$ of the boys and $80 %$ of the girls were successful. The percentage of failures was:

The correct option is D $32.8$
Number of failures
$= 40 %$ of $640 + 20 %$ of $360$
$= \frac{40}{100} \times 640 + \frac{20}{100} \times 360 = 256 + 72 = 328$
Total number of students $= 640 + 360 = 1000$
$∴ %$ of failures $= (\begin{matrix} \frac{328}{1000} \times 100 \end{matrix}) % = 32.8 %$ .