In an experiment, $1.0 g C a C O_{3}$ on heating evolved 224 mL of $C O_{2}$ at NTP. What mass of $C a O$ (calcium oxide) is formed?

0.56

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0.57

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0.58

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Solution

The correct option is A 0.56
$C a C O_{3} Δ ⟶ C a O + C O_{2} ↑$
Given 224 ml of $C O_{2}$ is formed.
1 mole of $C O_{2} = 224$ liter
$224 m L = \frac{224}{22.4 \times 10^{3}} = 10^{- 2}$ moles
Equal no. of molecules are formed from equation ,so moles of $C a O = 10^{- 2}$
Molar mass of $C a O = 40 + 16 = 56$
Mass of $C a O$ formed $= 56 \times 10^{- 2} = 0.56 g$

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