Question

In an experiment of verification of Ohm's law, following observations are obtained:

Potential difference V (in volt)	0.5	1.0	1.5	2.0	2.5
Current I (in ampere)	0.2	0.4	0.6	0.8	1.0

From observation table the resistance in circuit is

• A. $2.5\Omega$
• B. $2\Omega$
• C. $5\Omega$
• D. $3\Omega$

Answer 1

The correct option is A $2.5\Omega$

A currentvoltage characteristic or IV curve (currentvoltage curve) is a relationship, typically represented as a chart or graph, between the electric current through a circuit, device, or material, and the corresponding voltage, or potential difference across it.
In the graph, the voltage is plotted along the y-axis and the current is plotted along the x-axis. In the given example, the current I against the potential difference V, is a straight line with constant slope $1/R$ as the relation is linear and ohmic. That is, the remains constant for varying values of voltage and current.
The resistance can be found using the ohm's law which states $R=V/I=0.5/0.2or1.0/0.4$, etc will give $2.5$ ohms.
Hence, the resistance is 2.5 ohms.