In an experiment with a rectangular glass slab, for an angle of incidence of $60^{o}$ in air, angle of refraction is measured to be $r_{1}$ . When the glass slab is replaced by a hollow slab filled with water, angle of refraction is measured to be $r_{2}$ . Then :

r_{2} = r_{1}

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r_{2} > r_{1}

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r_{2} < r_{1}

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None of the above

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Solution

The correct option is B $r_{2} > r_{1}$
We know that $μ_{w} < μ_{g}$

Applying Snells law,

For glass,

$μ_{1} sin 60 = μ_{g} sin r_{1}$ ...(1)

For water,

$μ_{1} sin 60 = μ_{w} sin r_{2}$ ...(2)

From eq (1) & eq (2)

$μ_{g} sin r_{1} = μ_{w} sin r_{2}$

$\frac{μ_{g}}{μ_{w}} = \frac{sin r_{2}}{sin r_{1}} > 1$

So, $r_{2} > r_{1}$

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