In an ideal step-up transformer, the ratio of turns of primary to secondary is $1 : 10$ and primary voltage is $230 V$ . If the load current is $2 A$ , then current in the primary is

$20 A$

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$10 A$

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$2 A$

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$1 A$

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Solution

The correct option is A
$20 A$

Given $\frac{N_{P}}{N_{S}} = \frac{1}{10}$

We have $\frac{V_{P}}{V_{S}} = \frac{N_{P}}{N_{S}}$
Substituting the value we get $\frac{230}{V_{S}} = \frac{1}{10}$
Hence, $V_{S} = 2300$

In an ideal transformer, ther is no energy loss, the output power will be equal to the input power i.e.
Power in primary coil = power in secondary coil

$\Rightarrow$ $V_{P} I_{P} = V_{S} I_{S}$
substituting value will give $I_{P} = \frac{V_{S} I_{S}}{V_{P}} = \frac{2300 \times 2}{230} = 20 A$

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In an ideal step-up transformer, the ratio of turns of primary to secondary is 1:10 and primary voltage is 230 V. If the load current is 2A, then current in the primary is

In an ideal step-up transformer, the ratio of turns of primary to secondary is $1 : 10$ and primary voltage is $230 V$ . If the load current is $2 A$ , then current in the primary is