In an interchangeable assembly,

$A shaft of {20.00}_{- 0.005}^{+ 0.015} m m diameter$

$A hole of {20.00}_{+ 0.025}^{- 0.010} m m diameter$

form a mating pair in the worst assembly conditions, clearance between them will be

15 microns

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25 microns

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40 microns

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30 microns

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Solution

The correct option is D 30 microns
$In worst assembly condition, clearance will dia maximum.$

$Clearance(max) = Max hole dia - Min shaft dia$

$= 20.025 - 19.995$

$= 0.030 m m = 30 microns$

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