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Question

In an isosceles triangle ABC, AB = AC = 25 cm, BC = 14 cm, Calculate the altitude from A on BC.

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Solution

We know that altitude that is a perpendicular drawn on the unequal side of the isosceles triangle bisects that side.

Therefore, BD = DC = 7 cm.

Let us use the Pythagoras theorem in right angled triangle ADB we get,

Substituting the values we get,

Subtracting 49 from both the sides we get,

Let us take the square root we get,

AD = 24 cm

Therefore, the altitude of the isosceles triangle is .


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