Question

In an isosceles triangle $ABC,AB=AC=25cm,BC=14cm$. Calculate the altitude from $A$ on $BC$

Answer 1

$AC=25AB=25BC=14$

$DC=\frac{1}{2}\times BC=7\Rightarrow A{D}^{2}C{D}^2=A{C}^2$

$A{D}^2=625-49$

$A{D}^2=576$

$AD=24$

Altitude from $A$ or $BC$ is $24cm$