In an n – p – n transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector. Then
The emitter current will be 9 mA
The emitter current will be 11 mA
The base current will be 9 mA
The base current will be 0.1 Ma
Ic=10mAIc=90100IE⇒ IE=109×10mA=11.1mAIB=IE−IC=100T−10=109=1.1mA
In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (iE) and base current (iB) are given by