In an npn transistor, the collector current is 24 mA. If 80% of electrons reach collector, its base current in mA is
6
We know that, Ie = Ic + Ib
Given 80% of Ie = Ic = 24 mA
(80/100) Ie =24mA
Ie= (24×100)/80
Ie = 30 mA
Ib = Ie - Ic
= (30 - 24) mA
= 6 mA