Question

In an ordered set, half of them have values less than $\underset{–}{P}$ and half of them have values greater than $\underset{–}{Q}$. Choose the correct condition from the following.

• A. $\begin{array}{ccc}& P& Q\\ \left(a\right)& Median& Median\end{array}$
• B. $\begin{array}{ccc}& P& Q\\ \left(a\right)& Mean& Mean\end{array}$
• C. $\begin{array}{ccc}& P& Q\\ \left(a\right)& Mean& Median\end{array}$
• D. $\begin{array}{ccc}& P& Q\\ \left(a\right)& Median& Mean\end{array}$

Answer 1

The correct option is A $\begin{array}{ccc}& P& Q\\ \left(a\right)& Median& Median\end{array}$

Half of the total number in an ordered set have values less than the median and half of the total number have values greater than the median. Hence, P/Q is the median of the given set.