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Question

In an R-L-C series circuit shown in the figure, the readings of voltmeters V1 and V2 are 100 V and 120 V respectively. The source voltage is 130 V . For this situation, mark out the correct statement(s).


A
Voltage across resistor, inductor and capacitor are 50 V,503 V and (120+503) V respectively.
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B
Voltage across resistor, inductor and capacitor are 50 V,503 V and 120503 V respectively.
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C
Power factor of the circuit is 513.
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D
The circuit is capacitive in nature.
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Solution

The correct options are
A Voltage across resistor, inductor and capacitor are 50 V,503 V and (120+503) V respectively.
C Power factor of the circuit is 513.
D The circuit is capacitive in nature.
In R-L-C series circuit,
V2R+V2L=1002
(VcVL|=120

1302=V2R+(VCVL)2VR=50 V
Voltage across inductor, VL=1002502=503 V
and voltage drop across capacitor,
VC=(120+503V)
Power factor, cosϕ=VRVZ=50130=513
Since, VC>VL, so circuit is capacitive.

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