Question

In an right angle triangle ABC with right angle at B ,in which a = 24 units and b = 25 units and $\angle BAC=\theta$ then find $cos\theta$ and $tan\theta$

Answer 1

$C=AB=\sqrt{({25}^2-{24}^2)}$
$=\sqrt{(25+24)(25-24)}$
$=\sqrt{49}=7$
$cos\theta =\frac{adjacent}{hypotenuse}$
$=\frac{7}{25}$
$tan\theta =\frac{opposite}{adjacent}$
$=\frac{24}{7}$