Question

In an $\text{LCR}$ circuit the capacitance is made ${\frac{1}{4}}^{th}$ then what should be the change in inductance that the circuit remains in resonance again?

• A. $8\text{times}$
• B. $\frac{1}{4}\text{times}$
• C. $2\text{times}$
• D. $4\text{times}$

Answer 1

The correct option is D $4\text{times}$

$f_0=\frac{1}{2\pi \sqrt{LC}}$ .

To keep frequency unchanged $L$ be made 4 times.