In any ABC- - asin B- sin C-

The correct option is C 0 ∑ a(sin B sin C) =a(sin B sin C)+b(sin C sin A)+c(sin A sin B) =a(b c)+b(c a)+c(a b)2R [Using sine law of trian ...

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AM,GM,HM Inequality

In any ABC,...

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In any $△ A B C, \sum a (sin B - sin C) =$

2 s

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a^{2} + b^{2} + c^{2}

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none of these

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In any $△ A B C, \frac{1}{r_{1}^{2}} + \frac{1}{r_{2}^{2}} + \frac{1}{r_{3}^{2}} + \frac{1}{r^{2}}$ is equal to

A B C

\frac{sin A}{sin C} = \frac{sin A - B}{sin B - C}

a^{2}, b^{2}

c^{2}

A B C

\frac{b^{2} - c^{2}}{a^{2}} sin 2 A + \frac{c^{2} - a^{2}}{b^{2}} sin 2 B + \frac{a^{2} - b^{2}}{c^{2}} sin 2 C = 0

\frac{a sin (B - C)}{b^{2} - c^{2}} = \frac{b sin (C - A)}{c^{2} - a^{2}} = \frac{c sin (A - B)}{a^{2} - b^{2}}

△ A B C, \frac{sin A}{sin C} = \frac{sin (A - B)}{sin (B - C)},

a^{2}, b^{2}, c^{2}

A . P .

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