Question

In Bohr model of hydrogen atom, the ratio of periods of revolution of an electron in n = 2 and n = 1 orbits is

• A. 2 : 1
• B. 4 : 1
• C. 8 : 1
• D. 16 : 1

Answer 1

The correct option is C 8 : 1

According to Bohr model time period of electron $T\propto n^3\Rightarrow \frac{T_2}{T_1}=\frac{n_2^3}{n_1^3}=\frac{2^3}{1^3}=\frac{8}{1}\Rightarrow T_2=8T_1$