Question

In Bohr’s model of hydrogen atom, the ratio between the period of revolution of an electron in orbit n = 1 to the period of the electron in the orbit n = 2 is

• A. 1 : 2
• B. 2 : 1
• C. 1 : 4
• D. 1 : 8

Answer 1

The correct option is D 1 : 8

$\frac{T_1}{T_2}={\left(\frac{n_1}{n_2}\right)}^3={\left(\frac{1}{2}\right)}^3=\frac{1}{8}$
$T_1:T_2=1:8$