In Bohr's model, if the atomic radius of the first orbit $r_{1}$ , then radius of fourth orbit will be:

4 r_{1}

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6 r_{1}

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16 r_{1}

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\frac{r_{1}}{16}

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Solution

The correct option is C $16 r_{1}$
In Bohr's model, if the atomic radius of the first orbit $r_{1}$ , then the radius of the fourth orbit will be $16 \times r_{1}$ .

In general,

$r_{n} = n^{2} \times r_{1}$

$∴ r_{4} = 4^{2} \times r_{1}$

$∴ r_{4} = 16 \times r_{1}$

Hence, option $C$ is correct.

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