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Question

In both the cases, block & monkey are at the same horizontal level. In both the cases, monkey climbs the rope. In case-1 rope remains vertical & in case-2 rope swings during motion. t1 & t2 are times taken by monkeys to reach the pulley in case-1 & case-2 respectively. In both cases, monkey applies the same force on the rope.

A
t1=t2
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B
t1<t2
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C
In case-2, block reaches the pulley earlier than monkey
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D
In case-1, monkey reaches the pulley earlier than block
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Solution

The correct option is C In case-2, block reaches the pulley earlier than monkey
Monkey & block both reach the pulley at the same time. Upward acceleration
=Fmgm
Time taken by monkey to reach pulley in case-2 is more as compared to case-1.
Block will reach in the same time, but monkey have less acceleration in upward direction, as only a component of 'F' helps monkey to reach pulley.
t1<t2 and in case-2, block reaches the pulley earlier than monkey.

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