In $C_{4}$ plants, the primary $C O_{2}$ acceptor is

3-PGA

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Oxalo acetic acid

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RUBP

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PEP

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Solution

The correct option is C PEP
In $C_{4}$ pathway, first step is the carboxylation of PEP, which leads to production of oxaloacetic acid. Thus, in $C_{4}$ plants, the primary $C O_{2}$ acceptor is PEP. Thus, option D is correct.
Oxaloacetic acid and 3-PGA are the intermediate products of $C_{4}$ cycle. Thus, option A and B are wrong.

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C o_{2}

C_{3}

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Question 09
PEP is primary $C O_{2}$ acceptor in
(a) $C_{4}$ plants (b) $C_{3}$ plants
(c) $C_{2}$ plants (d) both $C_{3} a n d C_{4}$ plants

C O_{2}

C_{4}

C O_{2}

C_{4}

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