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Question

In Cannizaro reaction given below:
2PhCHO:OHPhCH2OH+PhCOO the slowest step is:

A
the attack of :OH at the carbonyl group
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B
the transfer of hydride to the carbonyl group
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C
the abstraction of proton from the carboxylic group
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D
the deprotonation of PhCH2OH.
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Solution

The correct option is B the transfer of hydride to the carbonyl group
Transfer of hydride ion from formed carboxylic acid to carbonyl carbon and it forms a stable product.
1174461_936084_ans_7094c4024fab4cb89396a20c7a167d6e.JPG

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