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Question

In Cannizzaro reaction given below:
Ph−CHOOH−−−−→Ph−CH2−OH+PhCOO−
The slowest step is:

A
The attack of OH at the carbonyl group
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B
The transfer of hydride to the carbonyl group
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C
The abstraction of proton from carboxylic acid
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D
The protonation of PhCOOH
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Solution

The correct option is B The transfer of hydride to the carbonyl group
The transfer of the hydride ion to the carbonyl group is the slowest or the rate determining step.

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