In Cannizzaro reaction given below-Ph - CHO Ph-CH2 - OH - PhCOO-The slowest step is-

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The Cannizaro Reaction

In Cannizzaro...

Question

In Cannizzaro reaction given below:
$P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}$
The slowest step is:

The attack of

O H^{-}

at the carbonyl group

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The transfer of hydride to the carbonyl group

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The abstraction of proton from carboxylic acid

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The protonation of

P h - C O O H

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Solution

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Similar questions

2 P h - C H O {O H}^{-} - ---------- \to P h - C H_{2} - O H + P h C O_{2}^{-}

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

2 P h C H O : O H \to P h C H_{2} O H + P h C O O^{-}

2 P h - C H O - O H ⟶ P h - C H_{2} O H + P H C O_{2}^{\oplus}

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