In carius method, 0.1775 g of an organic compound gave 0.2866 g of silver chloride. Calculate the percentage of chlorine in the compound.
[Molecular mass of $A g C l = 143.2 g / m o l$ ]

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Solution

Weight of the organic compound = 0.1775 g
Weight of the silver chloride = 0.2866 g
$% o f c h l o r i n e = \frac{W t o f A g C l \times 35.5 \times 100}{W t o f o r g a n i c c o m p o u n d \times 143.3}$

$= \frac{0.2866 \times 35.5 \times 100}{0.1775 \times 143.3} = 40$ %

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In carius method, 0.1775 g of an organic compound gave 0.2866 g of silver chloride. Calculate the percentage of chlorine in the compound. [Molecular mass of AgCl=143.2 g/mol]

Weight of the organic compound = 0.1775 g Weight of the silver chloride = 0.2866 g % of chlorine=Wt of AgCl×35.5×100Wt of organic compound×143.3 =0.2866×35.5×1000.1775×143.3=40%

In carius method, 0.1775 g of an organic compound gave 0.2866 g of silver chloride. Calculate the percentage of chlorine in the compound.
[Molecular mass of $A g C l = 143.2 g / m o l$ ]

Weight of the organic compound = 0.1775 g
Weight of the silver chloride = 0.2866 g
$% o f c h l o r i n e = \frac{W t o f A g C l \times 35.5 \times 100}{W t o f o r g a n i c c o m p o u n d \times 143.3}$

$= \frac{0.2866 \times 35.5 \times 100}{0.1775 \times 143.3} = 40$ %