In case of gaseous homogeneous reaction, the active mass of the reactant is given by the expression:

\frac{R T}{P}

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\frac{P}{R T}

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\frac{P V}{R T}

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\frac{n}{V} R T

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Solution

The correct option is B $\frac{P}{R T}$
$P V = n R T$
$\frac{n}{V} = \frac{P}{R T} =$ active mass (molarity)

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Similar questions

Q. Match the van der Waal's equation for one mole of gas given in column B to the conditions given in column A.

Column A	Column B
(A) High pressure	(i) $P V = R T + P b$
(B) Low pressure	(ii) $P V = R T - \frac{a}{V}$
(C) $P \to 0$	(iii) $P V = R T$
(D) Neither $a$ nor $b$ is negligible	(iv) $(P + \frac{a}{V^{2}}) (V - b) = R T$

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In case of gaseous homogeneous reaction, the active mass of the reactant is given by the expression:

The correct option is B PRTPV=nRTnV=PRT= active mass (molarity)

The correct option is B $\frac{P}{R T}$
$P V = n R T$
$\frac{n}{V} = \frac{P}{R T} =$ active mass (molarity)