Question

In case of projectile motion if two projectiles A and B are projected with same speed at angles ${15}^{\circ }$ and ${75}^{\circ }$ respectively to the horizontal then:

• A. $H_A=H_B$
• B. $H_A<H_B$
• C. $T_A=T_B$
• D. $T_A<T_B$

Answer 1

Answer: (B), (D)

$T_A<T_B$

$H_A=\frac{u^2{\text{sin}}^2{15}^{\circ }}{2g}$ and $H_B=\frac{u^2{\text{sin}}^2\left({75}^{\circ }\right)}{2g}$
Here, ${\text{sin}}^{2}75>{\text{sin}}^2{15}^{\circ }\therefore H_B>H_A$
Now, $T_A=\frac{2\text{u sin}{15}^{\circ }}{g},T_B=\frac{2\text{u sin}{75}^{\circ }}{g}$
$\therefore T_B>T_A$