In chromite ore, the oxidation number of iron and chromium reapectively, are:

+ 3, + 2

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+ 3, + 6

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+ 2, + 6

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None of this

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Solution

The correct option is C $+ 2, + 6$
The formulation for chromite ore is
$+ 2 F e [n C r O_{4}]^{- 2}$
$2 + n - 8 = 0$
$n = 6$
The oxidation state of chromium is $+ 6$ The oxidation state of iron is $+ 2$

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