In common base circuit of a transistor, current amplification factor is $0.95$ . Calculate the emitter current, if base current is $0.2 m A$ .

2 m A

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4 m A

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6 m A

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8 m A

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Solution

The correct option is B $4 m A$
Given, $α = 0.95, I_{b} = 0.2 m A$

As $α = \frac{I_{c}}{I_{e}} = \frac{I_{e} - I_{b}}{I_{e}} = 1 - \frac{I_{b}}{I_{e}}$

$\Rightarrow \frac{I_{b}}{I_{e}} = 1 - α = 1 - 0.95$

$\Rightarrow \frac{I_{b}}{I_{e}} = 0.05 \Rightarrow \frac{0.2}{0.05} m A = I_{e}$

$\Rightarrow I_{e} = 4 m A$

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In common base circuit of a transistor, current amplification factor is 0.95. Calculate the emitter current, if base current is 0.2 mA.

The correct option is B 4 mAGiven, α=0.95,Ib=0.2 mAAs α=IcIe=Ie−IbIe=1−IbIe⇒IbIe=1−α=1−0.95⇒IbIe=0.05⇒0.20.05 mA=Ie⇒Ie=4 mA

In common base circuit of a transistor, current amplification factor is $0.95$ . Calculate the emitter current, if base current is $0.2 m A$ .