In common base circuit of a transistor, current amplification factor is $0.95$ . Calculate the emitter current if base current is $0.2$ mA.

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Solution

The correct option is B $4$ mA
Given : $α = 0.95$ $I_{b} = 0.2$ mA
Current gain $β = \frac{α}{1 - α}$
$∴$ $β = \frac{0.95}{1 - 0.95} = 19$
Thus collector current $I_{c} = β I_{b}$
$∴$ $I_{c} = 19 \times 0.2 = 3.8$ mA
Emitter current $I_{e} = \frac{I_{c}}{α}$
$∴$ $I_{e} = \frac{3.8}{0.95} = 4$ mA

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In common base circuit of a transistor, current amplification factor is 0.95. Calculate the emitter current if base current is 0.2mA.

The correct option is B 4mAGiven : α=0.95 Ib=0.2 mACurrent gain β=α1−α∴ β=0.951−0.95=19Thus collector current Ic=βIb∴ Ic=19×0.2=3.8 mAEmitter current Ie=Icα∴ Ie=3.80.95=4 mA

In common base circuit of a transistor, current amplification factor is $0.95$ . Calculate the emitter current if base current is $0.2$ mA.