In common base mode of transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor $(β)$ will be

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Solution

The correct option is B 49
$I_{b} = I_{e} - I_{c}$ = 5.60 - 5.488 = 0.112 mA
$β = \frac{I_{e}}{I_{b}} = \frac{5.488}{0.112}$ = 49.

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In common base mode of transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor (β) will be

The correct option is B 49Ib=Ie−Ic = 5.60 - 5.488 = 0.112 mA β=IeIb=5.4880.112 = 49.

In common base mode of transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor $(β)$ will be

The correct option is B 49
$I_{b} = I_{e} - I_{c}$ = 5.60 - 5.488 = 0.112 mA
$β = \frac{I_{e}}{I_{b}} = \frac{5.488}{0.112}$ = 49.