We know that the sum of interior angles in a triangle is 180⁰.
Therefore, ∠A + ∠B+ ∠C = 180⁰
∠A + ∠B + 50⁰ = 180⁰
Since ∠A = ∠B, we can write it as,
2(∠A)+ 50⁰ = 180⁰
On simplifying we get,
2(∠A) = 130⁰
∠A = 65⁰
Hence option C is the answer.
In ΔABC, if ∠A = 50°, ∠B = 60°, then what is the measure of ∠C?