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Byju's Answer
Standard XII
Mathematics
Derivative of Standard Functions
In Δ A B C,...
Question
In
Δ
A
B
C
,
if
cos
A
a
=
cos
B
b
,
then show that it is
an isosceles triangle.
Open in App
Solution
In
△
A
B
C
,
⟹
cos
A
a
=
cos
B
b
⟹
cos
A
2
R
sin
A
=
cos
B
2
R
sin
B
⟹
cot
A
=
cot
B
⟹
A
=
B
⟹
△
A
B
C
is an isosceles triangle
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Similar questions
Q.
In
Δ
A
B
C
if
cos
A
a
=
cos
B
b
then it is an isosceles triangle. (With the standard notations.)
Q.
STATEMENT 1: In a
Δ
A
B
C
,
if
A
,
B
,
C
are in
A
.
P
. and triangle is equilateral, then
cos
A
+
2
cos
B
+
cos
C
=
2
.
STATEMENT 2: In a
Δ
A
B
C
, if
A
,
B
,
C
are in
A
.
P
. and
cos
A
+
cos
B
+
cos
C
=
2
,
then the triangle is isosceles.
Q.
In
Δ
A
B
C
,
if
cos
A
a
=
cos
B
b
,
then show that it is an isosceles triangle.
Q.
In a
Δ
A
B
C
,
if cos A =
s
i
n
A
2
s
i
n
C
,
show that the triangle is isosceles.
Q.
In
△
A
B
C
is
cos
A
a
=
cos
B
b
Show that it is an isosceles triangle.
(With the standard notations.)
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