Question

In $\Delta$ ABC, AB = BC and AC = CD and $\angle$B = x${}^0$ and $\angle$D = y${}^0$ then x${}^0$ +4 y${}^0$ equal -

• A. 360⁰
• B. 210⁰
• C. 180⁰
• D. 110⁰

Answer 1

The correct option is C

180⁰

$\angle$ACB = 2y

$\angle$ACB =$\angle$BAC

$\Rightarrow$ x + 2y+ 2y = 180${}^0$

$\Rightarrow$ x + 4y = 180${}^0$