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Question

In Δ ABC, AD is perpendicular to BC, then ACAB is equal to

A
sinCsinB
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B
cosBcosC
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C
sinBsinC
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D
tanBtanC
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Solution

The correct option is C sinBsinC
GivenADBC

InABD

ADAB=sinB(1)

andinADC

ADAC=sinC(2)

Dividing(1)by(2)weget

ACAB=sinBsinC

84176_97504_ans.png

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