In ΔABC and ΔDEF,AB=DF and ∠A=∠D. The two triangles will be congruent by SAS axiom if :
A
BC = EF
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B
AC = DE
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C
BC = DE
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D
AC = EF
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Solution
The correct option is B AC = DE If a triangle has to be congruent by SAS then two corresponding sides and the included angle of the triangles must be equal.
AB=DF and ∠A=∠D
Now we need the other set of equal sides which is AC and DE