In - ABC- - B- 900- AB- y units- BC- -3 units- AC- 2 units and angle A- x0- then sin x0 is -3m- where m is

sin x^∘ = sin A = BC/AC = √(3)/2 ...

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Semi Perimeter

In Δ ABC, ∠...

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In $Δ A B C, ∠ B = 90^{0}, A B = y u n i t s, B C = \sqrt{3} u n i t s, A C = 2 u n i t s$ and angle $A = x^{0}$ , then
$sin x^{0}$ is $\frac{\sqrt{3}}{m}$ , where m is

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