Question

In $\Delta$ ABC, $\angle B={90}^{\circ }$, AB = 6 cm and BC = 8 cm. The length of AC is

• A. 3 cm
• B. 10 cm
• C. 4 cm
• D. 7 cm

Answer 1

The correct option is B 10 cm

Given that in the $△ABC,\angle B={90}^{\circ }$

$\therefore △ABC$ is a right angle triangle.

So we can apply pythagoras theorem here.

$⟹A{C}^2=A{B}^2+B{C}^2$

$\therefore$Side, AC = $\sqrt{(6^2+8^2)}$ = 10 cm