Question

In $\Delta ABC$, D and E are two mid points of sides AB and AC respectively. If $\angle BAC={40}^{\circ }$ and $\angle ABC={65}^{\circ }$, then $\angle CED$ is

• A. 75
• B. 125
• C. 130
• D. 105

Answer 1

The correct option is D 105

Given that,
$\angle BAC={40}^{\circ }$
$\angle ABC={65}^{\circ }$
$\angle BCA={75}^{\circ }$
DE || BC,
$\angle AED=\angle ACB={75}^{\circ }$
$\angle CED={180}^{\circ }{75}^{\circ }={105}^{\circ }$