Question

In $\Delta$ ABC, the medians BE and CF intersect at G. AD is a line meeting BC at D. If GD is 1.5 cm, then find the value of AD.

Answer 1

$AG:GD=2:1\Rightarrow GD:AD=1:3$
$\Rightarrow AD:GD=3:1$
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$\frac{AD}{GD}=\frac{3}{1}$
$\Rightarrow \frac{AD}{1.5}=3$
$\Rightarrow AD=4.5$ cm.
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