Question

In $△$ABC, the medians BE and CF intersect at G. AD is a line meeting BC at D. If GD is 1.5 cm, then find the value of AD.

Answer 1

We know that,
The centroid of a triangle divides each median in the ratio 2 : 1.

$\therefore$ AG : GD = 2 : 1

$\Rightarrow$ GD : AD = 1 : 3

$\Rightarrow$ AD : GD = 3 : 1

$\frac{AD}{GD}$ = $\frac{3}{1}$

$\Rightarrow$ $\frac{AD}{1.5}$ = 3

$\Rightarrow$ AD = 4.5 cm.