In $△$ ABC, the medians BE and CF intersect at G. AD is a line meeting BC at D. If GD is 1.5 cm, then find the value of AD.

2.5 cm

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3 cm

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4 cm

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4.5 cm

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Solution

The correct option is D 4.5 cm
We know that,
The centroid of a triangle divides each median in the ratio 2 : 1.

$∴$ AG : GD = 2 : 1

$\Rightarrow$ GD : AD = 1 : 3

$\Rightarrow$ AD : GD = 3 : 1

$\frac{A D}{G D}$ = $\frac{3}{1}$

$\Rightarrow$ $\frac{A D}{1.5}$ = 3

$\Rightarrow$ AD = 4.5 cm.

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In triangle ABC, the medians BE and CF intersect at G. AD is a line meeting BC at D. If GD is 1.5 cm, then the value of AD is .

In $△$ ABC, the medians BE and CF intersect at G. AD is a line meeting BC at D. If GD is 1.5 cm, then find the value of AD.

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