In - OAB- if O-A-a- O-B-b- L is mid point of O-A- and M is point on O-B- such that O-M-M-B-2-1- If P is mid point of LM then A-P-

The correct option is A 13b⃗ 34a⃗ P.v. of L=a⃗2 (mid point of O⃗A⃗ )P.v. of M=2b⃗3 (use section formula)p.v. of P=a2+2b⃗32 #160; ...

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Section Formula

In Δ OAB, i...

Question

In $Δ O A B$ , if $\to O A = \to a, \to O B = \to b . L$ is mid point of $\to O A$ and $M$ is point on $\to O B$ such that $\to O M : \to M B = 2 : 1$ . If $P$ is mid point of $L M$ then $\to A P =$

\frac{1}{3} \to b - \frac{3}{4} \to a

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\frac{1}{3} \to b + \frac{3}{4} \to a

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\frac{1}{3} \to a - \frac{3}{4} \to b

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\frac{1}{3} \to a + \frac{3}{4} \to b

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\to a

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| \to a | = 1, ∣ ∣ \to b ∣ ∣ = 2

{(\to a + 3 \to b) \times (3 \to a - \to b)}^{2} =

\to a

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{(\to a + 3 \to b) \times (3 \to a - \to b)}^{2} =

2 \to a + 3 \to b - \to c, \to a - 2 \to b + 3 \to c, 3 \to a + 4 \to b - 2 \to c a n d \to a - 6 \to b + 6 \to c

\to a, \to b a n d \to c

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\frac{π}{3}

| \to a | = 1, | \to b | = 2, | \to c | = 3

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