Question

In $\Delta PQR$, $\angle P={37}^{\circ },\angle Q={105.5}^{\circ }.$ Find $\angle R.$

Answer 1

$\angle P={37}^o$

$\angle Q={105.5}^o$

$\angle P+\angle Q+\angle R={180}^o$

(Angle sum property)

$\angle R={180}^o-(37+105.5{)}^o$

$\angle R={37.5}^o$.