Question

Question 29

In $\Delta PQR$, if $\angle P={60}^{\circ }$ and $\angle Q={40}^{\circ }$, then the exterior angle formed by producing QR is equal to

a) ${60}^{\circ }$
b) ${120}^{\circ }$
c) ${100}^{\circ }$
d) ${80}^{\circ }$

Answer 1

As we know, the measure of exterior angle is equal to the sum of opposite two interior angles.

In $\Delta PQR,\angle x$ is the exterior angle
So, $\angle x=\angle P+\angle Q$
$={60}^{\circ }+{40}^{\circ }={100}^{\circ }$