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Question

In ΔPQR,PM is a median. If PM=26 cm and QR=24 cm, then find PQ2+PR2.

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Solution

In ΔPQR

PM is median

PM=26cm

QR=24cm

MR=QR2=242=12

QM=MR=12

In ΔPMR

(PR)2=(PM)2+(MR)2

(PR)2=(26)2+(12)2

=676+144

PR2=820

PR=2205

PQ=PR=2205

PQ2+PR2=(2205)2+(2205)2

=4(205)+4(205)

=820+820

=1640.

1225165_1501932_ans_0edb5bea87f44d648d0023fb009493fe.PNG

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