Question

In $\Delta PQR$ S is a point on PQ such that SR = QR = SP. and $\angle PSR={120}^{\circ }$ .Find $\angle P$ .

Answer 1

In $\Delta PRS$

$PS=SR⟹\angle P=\angle R=x$

$\angle S=120$

By Angle sum property

$x+x+120=180$

$2x=180-120$

$x=\frac{60}{2}=30$