Question

$S$ and $T$ are points on sides $PR$ and $QR$ of $\Delta PQR$ such that $\angle P=\angle RTS$. Show that $\Delta PRQ\sim \Delta RTS$.

Answer 1

$\sqrt{1}=\sqrt{2}=PQ=PR$

$\frac{QR}{QS}=\frac{QS}{PR}$

$In\Delta PQS\&\Delta TQR$

$\angle PQS=\angle TQR$

$\Delta PQS\sim \Delta TQR$