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Introduction to Sulphuric Acid

In detection ...

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In detection of 'P' by fusing with Na2O2 and then extracting it with water, we add HNO3(conc.) and ammonium molybdate to get 1. Yellow ppt of (NH3)PO4 2. Yellow ppt of (NH4)3PO4.12MoO3 3. White ppt of (NH4)3PO4 4. White ppt of (NH4)2HPO3

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Q. For the detection of phosphorus , the organic compound after fusion with

N a_{2} O_{2}

is extracted with water, boiled with

H N O_{3}

and then ammonium molybdate added to it. A yellow ppt. is obtained which is due to formation of :

Q. One of the oxoacid salts on heating with

c o n c . H N O_{3}

and ammonium molybdate, gives yellow ppt. What is this ion?

Q. (A) gives white ppt with

A g N O_{3}

N H_{3}

. (A) gives green ppt (B) with NaOH but ppt dissolves to yellow solution (C) when heated with

H_{2} O_{2}

. (C) gives yellow ppt (D) with

B a C l_{2}

.
According to above experiment complete the matrix.

Q. (A) (colourless solution) gives white ppt (B) with NaOH solution but ppt dissolves in excess of NaOH forming (C). (C) does not give ppt with

H_{2} S

but on boiling with

N H_{4} C l

, white ppt (B) appears. (A) also gives yellow ppt with

A g N O_{3}

State True or False.

A l B r_{3}

Q. Metal nitrate

(A)

on heating decomposes, leaving a residue

(B)

which goes into the solution with dil.

H C l

. The solution of

(B)

gives a white ppt. with an ammonium carbonate solution. Ppt.

C

dissolves in dil.

H C l

and the solution is treated with potassium chromate to yellow ppt.

(D)

V

H_{2} S O_{4}

also gives white ppt.

(E)

insoluble in dil.

H C l

and nitric acid. Precipitate

(E)

is part of white pigment lithopone.

The yellow precipitate

(D)

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