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Question

In Duma’s method of estimation of nitrogen, 0.55 g of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be:
(aq. tension at 300 K = 15 mm)

A
11.4%
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B
4.6%
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C
18.6%
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D
25%
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Solution

The correct option is A 11.4%
Volume of N2 at STP
(By gas equation):

p1×V1T1=p2×V2T2
Here
p1=ρρ1ρ=715 mm(pressure at which N2 collected)
ρ1=aqueous tension of water =15 mm

V2=(ρρ1)×V1T1×273760
V1=60 mL volume of moist nitrogen in nitro meter
p2=1 atm=760 mmT2=0C=273K

V2=(71515)×60300×273760=50.29 mL
%N2=2822400×V2W×100

W= Weight of organic compound.
%N2=2822400×50.290.55×100

%N2=11.43%

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